Problem 8-86 Inelastic collision - Part 4B
A large ball of modeling clay \((\text{mass}\; 4.5 \times 10^2\; g)\) is rolled on a tabletop so that it collides with a stationary small wooden box \((\text{mass} \; 7.9\times 10^2\; g)\). The collision is completely inelastic, and the ball and box then slide on the table for a distance of \(5.1 \;cm\). If the speed of the ball is \(2.2\; m/s\) just before the collision, determine: (a) the speed of the ball and box just after the collision (b) the magnitude of the friction force acting on the ball and box.
Accumulated Solution
\(m_1v_1 + m_2v_2 = (m_1 + m_2)v' \quad \; \text{where}\; v_2 = 0 \\ v{'} = 0.80\; m/s\; \text{ (answer to part (a))} \\ v_2 = v_0{^2} + 2ax \\ a = -6.24 \;m/s\)
\(v_2 = v_0{^2} + 2ax \\ 0 = 0.798^2 + 2a(5.1 \times 10^{-2} \;m) \\ a = -6.24\; m/s\)
This deceleration is a result of the friction force which we determine from:
(A) \(F = ma\)
(B) \(F = \mu FN\)
(C) \(F = (1/2)mv^2\)