Problem 8-75 Inelastic collision - Part 6 - B
Two trucks have a completely inelastic collision. After the collision, they have a common velocity of \(11 \;m/s\) at \(35^\circ\) south of west. Before the collision, one truck \((\text{mass} \; 2.3\times10^4\; kg)\) has a velocity of \(15\; m/s\) at \(51^\circ\) south of west. Determine the initial velocity (magnitude and direction) of the other truck \((\text{mass} \; 1.2\times10^4\; kg).\)
Accumulated Solution
\(v_{1x} = (-15) \cos 51 \\ v_{2x} = v_2 \cos \theta \\ v_x{'} = (-11) \cos 35 \\ m_1v_{1x} + m_2v_{2x} = (m_1 + m_2)v_x{'} \\ v_{2x} = -8.2\; m/s\)
Correct.
The conservation of Momentum in the \(y\) direction is:
\(m_1v_{1y} + m_2v_{2y} = (m_1 + m_2)v_y{'}\)
Before continuing calculate \(v_{2y}\)