Problem 7-62 Energy cons. with friction - Part 6 - A
A pen of mass \(0.057 \;kg\) is sliding across a horizontal desk. In sliding \(25 \;cm\), its speed decreases to \(5.7 \;cm/s\). What was its initial speed if the force of kinetic friction exerted on the pen by the desk is \(0.15\; N\) in magnitude? Use conservation of energy.
Accumulated Solution
\(E_K = (1/2)mv^2 \\ \text{Work against friction} = F_K \Delta x \\ (1/2)mv_0{^2} = (1/2)mv^2 + F_K \Delta x \)
Correct.
Before continuing, calculate \(v_0{^2}\) and \(v_0\)