Problem 4-72 Centripetal acceleration - Part 2 - B

To produce artificial gravity on a space colony, it is proposed that the colony should rotate. Suppose that the acceleration required is equal in magnitude to the acceleration due to gravity on the earth. For a colony that is $1.0 \;km$ in diameter, determine the frequency of rotation, the period of rotation, as well as the speed of a person at the edge of the colony (relative to the centre of the colony). [Ans. $2.2 \times 102\; Hz;$ $45\; s;$ $7.0 \times 101 \;m/s$]

Accumulated Solution

$a_c = v^2/r \\ a = 9.8 m/s^2$

Correct.

The numerical value of $r$ in this problem is:

(A)    $1.0$

(B)    $1.0\times10^3$

(C)    $0.5\times10^3$