Problem 2-43 - Free fall - Part 3 (b)

A baseball pitcher throws a ball vertically straight upward and catches it \(4.2\; s\) later. (a) With what velocity did the ball leave the pitcher's hand? (b) What was the maximum height reached by the ball?

Correct!

We know the acceleration (\(\mathrm{9.8\; m/s^2}\) down), the time of flight (\(4.2\; s\)) and the displacement.

The displacement is:
 
(A)  \(\mathrm{2\times \;the \;distance\; the\; ball \;rises}\)

(B)  \(\mathrm{9.8\; m}\)

(C)  \(\mathrm{0}\)