Problem 12-22 Simple circuit - Part 3 - A
In the figure, what are
(a) the current through the \(47\; \Omega\) resistor?
(b) the direction of the current through the \(47\; \Omega\) resistor?
(c) the potential difference \(V_A - V_B\)? \(V_B - V_A\)?
(d) the voltage across the \(84\; \Omega\) resistor?
(e) the potential at point \(C\), if we define the potential at the negative terminal of the battery to be zero?
Accumulated Solution
\(I = V/R \\ I = V/R = 6.0/131 = 0.046\; A \quad \text{(answer to part (a))}\)
Correct. Current flows \(+\) to \(-\), therefore A to B (answer to part (b))
The potential difference across the \(47\; \Omega\) resistor is:
(A) \(47\; V\)
(B) \(6\; V\)
(C) \(2.2\; V\)
(D) \(0.046 \;V\)