Problem 12-14 Ohm's law - Part 5 - A

Diagram of circuit with current of 2.38 A

In the circuit above the current is \(2.38\; A\).­ What are

(a) the resistance \(R\)?
(b) the direction of the current through the resistor?
(c) the potential difference \(V_A - V_C\)?

[Ans. (a) \(1.36\; \Omega\)   (b) \(\text{toward top of diagram}\)   (c) \(3.24\; V\)]

Accumulated Solution

\(V_R = 3.24\; V \\ R = \Delta V/I = (3.24 \;V)/(2.38\; A) = 1.63\; \Omega \\ \text{A is connected to the + side of the battery and is at the higher potential.} \\ \text{Current is the flow of positive charge which flows from higher to lower potential, i.e. A to B.}\)

No. Potential at \(A\) is higher than at \(B\) and \(V_B – V_C = 0\)

Try again.