Problem 11-55 Potential and kinematics in thundercloud - Part 7 - B
Under a particular thundercloud, there is a uniform electric field of \(9.3 \times10^3\; V/m\) upward.
An electron in the field, initially at rest, travels freely for \(3.5 \times 10^{-6} \; m\) before undergoing a collision with a gas molecule. Just before it hits the molecule, what is its speed? Use energy methods.
[Ans. \(1.1 \times 10^5\; m/s\)]
\(E_{K1} + U_1 = E_{K2} + U_2 \\ U = qEy \)
Correct!
Before continuing calculate the value of \(v_2{^2}\) and \(v_2 \).