Problem 11-35 Potential and kinematics - Part 3B - B

A proton is accelerated from rest from a positively charged plate to a parallel negatively charged plate. The separation of the plates is $8.9\; mm.$ If the potential difference between the plates is $75.3\; V,$ what is the speed of the proton just as it hits the negative plate?
[Ans. $1.2 \times 10^5\; m/s$]

Accumulated Solution

No. The equation is incorrect; you can see this with a simple dimensional analysis. The units of $V$ are joules/coulomb and of $q$ are coulombs. What are the units of $q/V$? Is $q/V$ an energy?

Try again.