Problem 10-49 Electron deflection - Part 2 - C

An electron in an oscilloscope beam travels between the deflecting plates with an initial velocity of $2.0 \times 10^7\; m/s$ parallel to the plates, which lie in a horizontal plane. The electric field is $2.2 \times 10^4\; N/C$ downward, and the plates have a length of $4.0\; cm.$ When the electron leaves the plates, (a) how far has it dropped or risen? (Specify which.) (b) what is its velocity (magnitude and direction)?
[Ans. (a) risen $7.7 \times 10^{-3}\; m$   (b) $2.1 \times 10^7\; m/s\; \text{ at} \;21 ^\circ$ above horizontal]

Accumulated Answer

No. What is the definition of $E$?

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