Problem 11-35 Potential and kinematics - Part 3B - A

A proton is accelerated from rest from a positively charged plate to a parallel negatively charged plate. The separation of the plates is \(8.9\; mm.\) If the potential difference between the plates is \(75.3\; V,\) what is the speed of the proton just as it hits the negative plate?
[Ans. \(1.2 \times 10^5\; m/s\)]

Accumulated Solution

Proton diagram B

\(U = qV\)

Correct!

Conservation of energy says that:

(A)   \(mv_1 = mv_2\)

(B)   \(E_{K1} + U_1 = E_{K2} + U_2\)

(C)   \(U_1 = U_2\)