Problem 10-31(a) Vector electric field - Part 8 - A

The figure shows the positions of two a particles (charge on each is $+2e$) and an electron. What are the magnitude and direction of
(a) the resultant force on the electron?
(Hint: choose the $+x$ axis along the line from the electron to the right-hand a particle.)

[Ans.(a) $1.31 \times 10^{-8} N$ at $13.3^\circ$ to left of line from electron to right-hand a]

Accumulated Solution

$F_{1x} = F_1, F_{2x} = F_2 \cos 53.1 \\ F_{1y} = 0, F_{2y} = F_2 \sin 53.1 \\ F_1 = 1.045 \times 10^{-8} N \\ F_2 = 3.76210^{-9} N$

No. These are vector components so you must use the Pythagorean theorem.

Try again.