Problem 7-83 Power - Part 3 - B

A \(2.65-kW\) motor is used to lift crates vertically upward in a factory. What is the maximum speed at which a crate of mass \(147\; kg\) can be lifted by this motor? Assume that all the motor's power goes into lifting. (Hint: determine the height that the crate can be lifted in \(1.00\; s\).) [Ans. \(1.84\; m/s\)]

Accumulated Solution
 
\(P = 2.65\times10^3\; W \\ E = Pt\)

Correct!

\(E = (2.65\times 10^3 \;W)(1.0\; s) = 2.65\times10^3\; J\)

This energy goes into (read question again):

(A)  \(E_K = ½ \;mv^2\)

(B)  \(E_P = mgh\)

(C)  \(\text{Heat}\)