Problem 6-11 Dynamics with friction - Part 4 - C
A child is sliding down a water slide inclined at 25∘ to the horizontal. The coefficient of kinetic friction between the child and the slide is 0.10. What is the magnitude of the acceleration of the child? (Hint: FN is not equal to mg.)
Accumulated Solution
Correct! ∑Fy=FN−mgcos25=0
Therefore FN=mgcos25 and f=μFN=(0.10)(m)(9.8)cos25=0.888m
The correct expression in the x-direction is:
(A) mg−f=ma
(B) mgcos25−f=ma
(C) mgsin25−f=ma