Problem 5-57 Translational Equil.- Part 4 - B
A sign outside a hair stylist's shop is suspended by two wires. The force of gravity on the sign has a magnitude of 55.7N. If the angles between the wires and the horizontal are as shown in the figure, determine the magnitude of the tensions in the two wires.
[Ans. T1=49.9N; T2=40.8N]
Accumulated Solution
a=0∑Fx=0,∑Fy=0
Correct!
In fact both (B) and (C) are correct
(B) ∑F=0
(C) ∑Fx=0, ∑Fy=0
It is (C) which is most useful and will be used here (and in most cases).
Let us look at the x-component first.
The x-components of the forces T1, T2 and 55.7N are:
(A) T1x=T1cos45;T2x=T2cos30;0
(B) T1x=−T1cos45;T2x=T2cos30;0
(C) T1x=−T1cos45;T2x=−T2cos30;0
(D) T1x=T1cos45;T2x=−T2cos30;0